# Line slope calculator x+5y=9

**Straight line given by points A[4; 1] and B[9; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+1.8

**Canonical form of the line equation:**x+5y-9 = 0

**Parametric form of the line equation:**

x = 5t+4

y = -t+1 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 1.8

**Distance line from the origin:**d

_{0}= 1.765

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[6.5; 0.5]

**Perpendicular Bisector equation:**5x-y-32 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (9; 0) ; |OB| = 9**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 14°2'10″ = 0.245 rad**