# Line slope calculator 2x+5y=40

**Straight line given by points A[0; 8] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+8

**Canonical form of the line equation:**2x+5y-40 = 0

**Parametric form of the line equation:**

x = 5t

y = -2t+8 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 20

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 7.4278

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[2.5; 7]

**Perpendicular Bisector equation:**5x-2y+1.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 39°48'20″ = 0.6947 rad**